AB – circle diameter, AB = 13. CD – chord, CD perpendicular to AB And CD intersects AB at point K, SK = 6. Find the smallest
| November 16, 2020 | education
AB – circle diameter, AB = 13. CD – chord, CD perpendicular to AB And CD intersects AB at point K, SK = 6. Find the smallest of the segments into which point K divides the diameter AB.
CD_ | _AB⇒CK is the height of a right-angled triangle ACB CK² = AK * KV, AK
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