AB circle diameter, AC- chord, BOC = 48 degrees find angle ACO.

The angles AOC and BOC are adjacent, the sum of which is 180, then the angle AOC = (180 – 48) = 132.

The AOC triangle is isosceles, since OA = OC = R, then the angle OAC = OCA = (180 – AOC) / 2 = (180 – 132) / 2 = 48/2 = 24.

Answer: Angle ACO = 24.



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