AB-diameter of a circle centered at O. BC-chord. BOC = 60 degrees. The length of the chord BC

AB-diameter of a circle centered at O. BC-chord. BOC = 60 degrees. The length of the chord BC is known to be equal to the radius of the circle. Find ABC.

Let’s build the radius of the OС circle.
By condition, the angle ВOС = 60.
In the ВOС triangle, OB = OС = R, and according to the condition, the BC chord is also equal to the radius of the circle, then the ВOС triangle is equilateral, then all its internal angles are 60.
OBC angle = ABC = 60.
Answer: The angle ABC is 60.



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