AB-diameter of a circle centered at the point O. BC-chord. It is known that the angle AOC = 130
| April 28, 2021 | education
AB-diameter of a circle centered at the point O. BC-chord. It is known that the angle AOC = 130 degrees. Find the corners of the triangle BOC.
The angle AOC and the angle BOC are adjacent angles, the sum of which is 180, then the angle BOC = 180 – AOC = 180 – 130 = 50.
The BOS triangle is isosceles, since OS = OB = R. Then the angle OСB = OBC = (180 – ВOС) / 2 = (180 – 50) / 2 = 130/2 = 65.
Answer: The angles of the BOC triangle are 65, 65, 50.
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