ABC, angle C is 90, AC = 1 BC = √15 find SinB.
| May 23, 2021 | education
sin B = AC / AB, but in the task only AC and BC are given, First we find AB. Since the angle ACB is ninety degrees, the opposite side is the hypotenuse, which means AB is the hypotenuse. Let’s find it:
AB = √ (BC ^ 2 + AC ^ 2) = √ (√15 ^ 2 + 1 ^ 2) = √ (15 + 1) = √ 16 = 4.
sin B = AC / AB = 1/4 = 0.25.
The ABC angle is approximately 14-15 degrees.
Answer: sin B = 1/4.
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