ABC is a right triangle. AB = 8 BC = 10 Angle A = 90 ° AD perpendicular to BC Find- AD.

Determine the value of AC:

AC ^ = BC ^ – AB ^ = 100 – 64 = 36.

AC = 6.

In triangle ABC we find sinACB = AB / BC = 0.8.

Take a right-angled triangle ADC. Taking into account that ACB and ACD are the same angle, we compose the equation:

sinACD = AD / AC.

Whence it follows: AD = AC * sinACD = 6 * 0.8 = 4.8.

Answer: AD = 4.8.



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