ABC is an isosceles triangle. The AC side is longer than the AB side by 5cm. What are the sides

ABC is an isosceles triangle. The AC side is longer than the AB side by 5cm. What are the sides of the triangle side if P (ABC) = 52cm?

Let the length of the side AB of the isosceles triangle ABC be equal to X centimeters. Then the side of the speaker is (X + 5) centimeters (since it is 5 centimeters longer, by condition).
Since this triangle ABC is isosceles, then let the AC side = BC = X + 5 centimeters.
It is known that the perimeter of this triangle ABC is 52 centimeters. And we know that the perimeter of a triangle is the sum of the lengths of all its sides, that is:
P = AB + BC + AC.
Knowing this, we will compose and solve the equation:
X + (X + 5) + (X + 5) = 52;
Let’s expand the brackets:
X + X + 5 + X + 5 = 52;
Let’s transform the expression:
3X + 10 = 52;
3X = 52 – 10;
3X = 42;
X = 42: 3;
X = 14.
Thus, AB = 14 centimeters.
Let’s find the length of the AC side and, accordingly, BC:
14 + 5 = 19 (centimeters) – the length of the speaker side.
And since ABC is an isosceles triangle, AC and BC are the sides, and AC = BC = 19 centimeters.
Answer: 14 centimeters; 19 centimeters; 19 centimeters.