ABC-isosceles triangle AC-base Angle B is 30 degrees greater than angle A. Find the angles of triangle ABC

As you know, the sum of the angles of any triangle is 180 °.

Since the condition indicates that the base of the triangle is AC, then angle B is its apex, and angles A and C are equal to each other.

We draw up an equation in which the value of the angle A and C is taken equal to x °.

Since the angle B is 30 ° more, it will be equal to: x + 30 °.

The sum of the angles of the triangle will be:

x + x + x + 30 = 180.

3 * x = 180 – 30.

3 * x = 150.

x = 150/3 = 50 ° (angle A and C).

x + 30 = 50 + 30 = 80 ° (angle B).

Answer: 50 °, 80 °, 50 °.