ABC-right triangle AB = BC BD-bisector M (belongs to) BD K (belongs to) AC MK || AB Angle ABC = 126 degrees

ABC-right triangle AB = BC BD-bisector M (belongs to) BD K (belongs to) AC MK || AB Angle ABC = 126 degrees. Angle BAC = 27 degrees Find Angle MKD.

1st simplest option:
<BAC and <MKD – corresponding with AB || MK =>
m (<MKD) = m (<BAC) = 27
2nd option:
AB || MK => By the main similarity theorem => triangles ABD and KMD are similar => m (<MKD) = m (<BAC) = 27
Answer: 27



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