ABC unfolded angle. BH-inner corner ABH: BHC = 6: 3. Find ABH and HBC.

Let the AВН angle be (6x) °, then the ВНС angle – 3x °.
Because ABC – unfolded angle, then ABC = 180 °
since angle ABC = angle ABН + angle ВНС, then we will draw up an equation and solve the problem.
6x + 3x = 180
9x = 180 | : nine
x = 20
If x = 20, then the angle ABН = 20 * 6 = 120 °
and then the ВНС angle = 3 * 20 = 60 °
Answer: AВН = 120 °, ВНС = 60 °