ABCD is a parallelogram, the bisector of angle A intersects the side BC at point M, the angle CDA
| June 20, 2021 | education
ABCD is a parallelogram, the bisector of angle A intersects the side BC at point M, the angle CDA is 134 degrees. Find the angle CMA.
The sum of the adjacent angles of the parallelogram is 180, then the angle ВСD = 180 – АDC = 180 – 134 = 46.
Since AM is the bisector of the angle, it divides the BAD angle in half, the MAD angle = 46/2 = 23.
Then, in the quadrangle AMCD, the angle CMA = 360 – 134 – 46 – 23 = 157.
Answer The CMA angle is 157.
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