ABCD is a rectangle, AC meets BD at point O, angle AOB = 60 degrees Find the angles of triangle ADO.

Angles AOB and AOD are adjacent angles, the sum of which is 180, then the angle AOD = 180 – AOB = 180 – 60 = 120.

The diagonals of the rectangle, at the point of intersection, are divided in half, then the triangle AOD is isosceles, OA = OD.

In an isosceles triangle, the angles at the base are equal, then the angle OAD = ODA.

The sum of the interior angles of the triangle is 180, then OAD + ODA + 120 = 180.

Angle OAD = ODA = (180 – 120) / 2 = 30.

Answer: The angles of the AOD triangle are 30, 120, 30.