ABCD is a rectangle. AD = 6cm, DB = 20cm, O is the intersection point of the rectangle

ABCD is a rectangle. AD = 6cm, DB = 20cm, O is the intersection point of the rectangle diagonals, Find the perimeter of the triangle BOC.

Since ABCD is a rectangle, then its opposite sides are equal, then BC = AD = 6 cm.
For a rectangle, the diagonals are equal, AC = BC = 20 cm, and the point of their intersection divides them in half, then OB = OC = 20/2 = 10 cm.
Determine the perimeter of the BOS triangle.
Pvos = BО + CO + BC = 10 + 10 + 6 = 26 cm.
Answer: The perimeter of the BOС triangle is 26 cm.



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