ABCD is a rectangle, O is the intersection point of the diagonals. Find the sides of the triangle AOB

ABCD is a rectangle, O is the intersection point of the diagonals. Find the sides of the triangle AOB if CD = 5 cm and AC = 8 cm.

To complete this task, consider the condition and analyze it;

Since the given shape is a rectangle by the condition of setting, let’s recall its properties;

In a rectangle, the diagonals are equal and are halved at the point of intersection;

This property will help us in solving the problem;

Another property of the rectangle; In a rectangle, opposite sides are equal, which means that side CD = AB = 5cm. One side of the triangle was found;

Since the diagonals of the rectangle are halved, it means AO = 1/2 AC;

AO = 1/2 * 8 = 8/2 = 4cm – the second side of the triangle;

And since the diagonals are equal and are divided in half, it means the triangle is isosceles, which means AO = BO = 4cm;

Answer: AB = 5cm; AO = VO = 4cm.



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