ABCD is a rectangular trapezoid, AD is perpendicular to AB.AD = 6, angle BCD = 60 degrees. Find BC.

From the top B of the trapezoid, we will construct the height ВН.

Since the trapezoid is rectangular, and BH is the height, then the quadrangle ABHD is a rectangle, and then BH = AD = 6 cm.

In a right-angled triangle ВСН, the angle С, by condition, is equal to 60, then Sin60 = ВН / ВС.

ВС = ВН / Sin60 = 6 / (√3 / 2) = 12 / √3 = 12 * √3 / 3 = 4 * √3 cm.

Answer: The length of the BC side is 4 * √3 cm.



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