ABCD is an isosceles trapezoid. Bases AD = 10, BC = 6, AC = 10. Calculate the area of a trapezoid

Let’s draw the height of the CH trapezoid ABCD.

Since the trapezoid is isosceles, the height CH divides the larger base into segments, the length of the larger of which is: DH = (AD + BC) / 2 = (10 + 6) / 2 = 16/2 = 8 cm.

The ACН triangle is rectangular, then CH ^ 2 = AC ^ 2 – AH ^ 2 = 100 – 64 = 36.

CH = 6 cm.

Determine the area of the trapezoid.

Savd = (ВС + АD) * СН / 2 = (6 + 10) * 6/2 = 48 cm2.

Answer: The area of the trapezoid is 48 cm2.



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