ABCD is an isosceles trapezoid, in it BE || CD, angle A = 40, angle ABE = 75. You need to find all the corners.

In triangle ABE, we determine the value of the angle AEB. Angle AEB = 180 – 75 – 40 = 65.

The angle AEB and DEB are adjacent angles, then their sum is 180, which means the angle BED = 180 – 65 = 115.

Since, according to the condition, BE is parallel to CD, and BC and AD are parallel as the bases of a trapezoid, then BCDE is a parallelogram, in which the opposite angles are equal. Then the angle ВСD = ВD = 115.

The sum of the angles at the side of the trapezoid is 180, then the angle CDA = 180 – 115 = 650, the angle ABC = 180 – 40 = 140.

Answer: The angles of the trapezoid are equal: 40, 140, 115, 65.