ABCD-parallelogram, AM-bisector kuta A, BM = 4, CM = 2. Find the perimeter of the parallelogram ABCD.
| March 15, 2021 | education
1. In accordance with the properties of the parallelogram, the bisector AM separates the isosceles triangle ABM from it. The sides BM and AB of the specified triangle have the same length, that is, AB = BM = 4 centimeters.
2. BC = 4 + 2 = 6 centimeters.
3. Considering that the sides of the parallelogram opposite each other are equal, we calculate the perimeter (P) of this geometric figure:
P = 2 (AB + BC) = 2 (4 + 6) = 20 centimeters.
Answer: P = 20 centimeters.
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