ABCD parallelogram angle C = 45 degrees BD perpendicular to AB, BD = 7, find -DC.
| February 27, 2021 | education
Diagonal BD divides the parallelogram into two triangles, ABD and BCD.
Angle ABD = BDC as criss-crossing angles at the intersection of parallel straight lines AB and CD of secant BD, then angle ABD = BDC = 90, then triangle BCD is rectangular.
In a right-angled triangle ВСD, one of the acute angles is 45, then the triangle ВСD is equilateral, ВD = СD = 7 cm.
Answer: The length of the CD side is 7 cm.
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