ABCD – parallelogram, drawn by AB = BN and DM = AD. Prove: CM = CN.
| August 12, 2021 | education
Having drawn the segments BN and DM, we get two triangles: ΔBNC and ΔDСM.
Because the opposite sides of the parallelogram are equal, then AB = CD = BN; AD = BC = BM.
In this case, the angle NBC and the angle CDM are also equal (since the angles for parallel lines and secant are equal).
Using the first sign of equality of triangles, we can say that ΔBNC and ΔDCM are equal triangles, hence NC = CM.
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