ABCD rectangle AD-6cm BD10 cm O-intersection of the diagonal of the triangle Find the perimeter of the triangle BOC?

Since ABCD is a rectangle, then its opposite sides are equal, then BC = AD = 6 cm.

For a rectangle, the diagonals are equal, then AC = BC = 10 cm, and the point of intersection divides them in half, then OB = OC = 10/2 = 5 cm.

Let’s define the perimeter of the triangle BОС.

Рвос = BО + СО + ВС = 5 + 5 + 6 = 16 cm.

Answer: The perimeter of the BOС triangle is 16 cm.



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