ABCD- rectangle BD = 16cm, AB = 10cm. Find the perimeter of triangle COD, where O is the enumeration point of the diagonals

AB = СD = 10 (cm). (the parallel sides of the rectangle are equal).
CO = OD = 8 (cm). (the diagonals of the rectangle are equal and the intersection point is halved)
P = 8 + 8 + 10 = 26 (cm)
Answer: 26



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