ABCD-rectangle, O-point of intersection of its diagonals. The AOB is 48 degrees. Find the corner ADB.

univerkov | June 24, 2021 | education

Angle AOD = 180 ° – 48 ° = 132 ° (since the angles AOB and AOD are adjacent, and the sum of adjacent angles is 180 °).
AO = OD (since the diagonals of the rectangle are halved by the intersection point and are equal).
Therefore, triangle AOD is isosceles, which means the angles at the base are equal.
Angle ADB = (180 – 132) / 2 = 48/2 = 24 °. (since triangle AOD is isosceles).
Thus, we found the degree value of the ADB angle, and it is equal to 24 °.
Answer: The ADB angle is 24 °.

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