ABCD-rectangle, perimeter ABC = 22cm. AD is 5 cm larger than AB. Find the area.

Suppose that AB = x, then AD = x + 5. Knowing what the perimeter of the rectangle is, we can compose the equation:

(x + (x + 5)) * 2 = 22;

x + x + 5 = 22: 2;

2x + 5 = 11;

2x = 11 – 5;

2x = 6;

x = 6: 2;

x = 3.

So AB = 3 cm, then AD = 3 + 5 = 8 cm.Thus, we learned the length and width of the rectangle, it follows that S = 3 * 8 = 24 cm ^ 2.

Answer: the area of the rectangle is 24 cm ^ 2.