ABCD rhombus AB = 5cm BC = 6cm. AC find the length of the diagonal.

Since the diagonals of the rhombus, at the point of intersection, intersect at right angles and are divided in half, then BO = DO = BD / 2 = 6/2 = 3 cm, AO = CO = AC / 2, and triangle AOB is rectangular.

Then, by the Pythagorean theorem, AO ^ 2 = AB ^ 2 – BO ^ 2 = 25 – 9 = 16.

AO = 4 cm, then AC = 2 * AO = 2 * 4 = 8 cm.

Answer: The AC diagonal is 8 cm.



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