ABCD- trapezoid angle A 48 angle C 62 find angles B, D.

ABCD is a trapezoid.

A trapezoid is a quadrilateral in which two sides are parallel and the other two sides are not parallel.

Angle A = 48 degrees.

Angle C = 62 degrees.

BC is parallel to AD (by definition of a trapezoid).

Angle A + angle B = 180 degrees (by the property of inner one-sided angles when BC is parallel to AD and secant to AB).

Angle B = 180 degrees – angle A.

Angle B = 180 degrees – 48 degrees.

Angle B = 132 degrees.

Angle C + angle D = 180 degrees (by the property of inner one-sided angles when BC is parallel to AD and secant to DC).

Angle D = 180 degrees – angle C.

Angle D = 180 degrees – 62 degrees.

Angle D = 118 degrees.

Answer: Angle B = 132 degrees; Angle D = 118 degrees.



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