ABCDA1B1C1D1 rectangular parallelepiped Find the area of the base if AA1 = 4, AB = 2, BD1 = 6.
| September 23, 2021 | education
Let’s draw a diagonal BD at the base of the parallelepiped.
In a right-angled triangle DD1B BD ^ 2 = BD1 ^ 2 – DD1 ^ 2 = 36 – 16 = 20.
In a right-angled triangle ABD AD ^ 2 = BD ^ 2 – AB ^ 2 = 20 – 4 = 16.
AD = 4 cm.
Then the area of the base of the parallelepiped is: Sbn = AB * AD = 2 * 6 = 12 cm2.
Answer: The base area is 12 cm2.
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