AC and BD are diameters of a circle centered on O. Center angle AOD is 118 °. Find the inscribed angle ACB.
| October 12, 2021 | education
The AOD angle is equal to the BOC angle as the vertical angles at the intersection of the AC and BD diameters, then the BOC angle = 118.
The BОС triangle is isosceles, since its sides ОВ and ОВ are the radii of the circle, then the angle СBО = ОСB = (180 – BОС) / 2 = (180 – 118) / 2 = 31.
Angle ACB = OCB = 31, since point O lies on the diagonal AC
Answer: Angle AOD is 31.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
