AC and BD are diameters of a circle with center O. Angle ACB is 34. Find the angle AOD.
| April 11, 2021 | education
The ВOС triangle is isosceles, since the OB and OC are circular radii, then the angle OBC = OCВ = ACB = 34. Angle ВOС = (180 – OBC – OСВ) = (180 – 34 – 34) = 122.
Angle AOD = BOC = 112 as the vertical angles at the intersection of the diagonals AC and BD.
Answer: Angle AOD is 112.
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