AC and BD are the diameters of the circle centered on O. Angle ACB is 22 / Find the angle AOD.
| March 19, 2021 | education
The triangle BОС is isosceles, since its sides ОB and ОB are the radii of the circle, then the angle СBО = ОСB = АСB = 22.
The sum of the inner angles of the triangle is 180, then the angle BОС = 180 – ВСО – СВО = 180 – 22 – 22 = 136.
The AOD angle is equal to the BOC angle as the vertical angles at the intersection of the AC and BD diameters, then the AOD angle = 136.
Answer: Angle AOD is 136.
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