AC-diameter, CD-chord of a circle centered at point O. LAOD = 145 degrees. Find the corners of the COD triangle.

The angles AOD and DОС are adjacent angles, the sum of which is 180, then the angle DОС = 180 – AOD = 180 – 145 = 35.

The DОС triangle is isosceles, since ОD = ОС = R, then the angle ОDC = ОСD = (180 – DОС) / 2 = (180 – 35) / 2 = 145/2 = 72.5.

Answer: The angles of the COD triangle are 35, 72.5, 72.5.



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