Triangle AOB is isosceles, since OA and OB are circle radii.
Then the angle BAO = BAO = (180 – AOB) / 2 = (180 – 146) / 2 = 34/2 = 17.
By the property of a tangent drawn to a circle, the radius drawn to the tangent from the center of the circle is perpendicular to the tangent. Then the angle CAO = 90.
Angle BAC = CAB – BAO = 90 – 17 = 63.
Answer: The BAC angle is 63.
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