According to the reaction equation Fe (OH) 2 = FeO + H2O, determine the mass of iron (II) oxide formed

According to the reaction equation Fe (OH) 2 = FeO + H2O, determine the mass of iron (II) oxide formed during the decomposition of 45g. starting material.

1. Fe (OH) 2 = FeO + H2O – decomposition, iron oxide (2) was formed;
2. We make calculations:
M Fe (OH) 2 = 89.8 g / mol;
M (FeO) = 71.8 g / mol.
3. Determine the amount of the original substance:
Y Fe (OH) 2 = m / M = 45 / 89.9 = 0.5 mol;
Y (FeO) = 0.5 mol since the amount of these substances is 1 mol, which confirms the equation.
4. Find the mass of the product:
m (FeO) = Y * M = 0.5 * 71.8 = 35.9 g.
Answer: Received iron oxide (2) weighing 35.9 g.