According to the reaction equation zno + c → co2 + zn, calculate the mass of the formed

According to the reaction equation zno + c → co2 + zn, calculate the mass of the formed carbon monoxide if zinc oxide reacted 40.5 g

Let’s find the amount of zinc oxide substance ZnO by the formula:

n = m: M.

M (ZnO) = 65 + 16 = 81 g / mol.

n = 40.5 g: 81 g / mol = 0.5 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2ZnО + C = 2Zn + СО2 ↑.

According to the reaction equation, there is 1 mole of carbon monoxide for 2 mol of zinc oxide. Substances are in quantitative ratios of 2: 1.

The amount of carbon monoxide substance will be 2 times less than zinc oxide.

2n (ZnO) = n (CO2) = 0.5: 2 = 0.25 mol.

Find the mass of carbon monoxide.

m = n × M,

M (CO2) = 44 g / mol.

m = 0.25 mol × 44 g / mol = 11 g.

Answer: 11 y.