Acute angle of a rectangular trapezoid 60 and base 10, 12 find the area of the trapezoid
| August 22, 2021 | education
Let’s build the height of the CH trapezoid ABCD. Quadrangle ABCН is a rectangle, then AH = BC = 10 cm.
The length of the segment DH = AD – AH = 12 – 10 = 2 cm.
In a right-angled triangle СDН, we determine the length of the leg СН.
Tg60 = CH / DН.
CH = DH * tg60 = 2 * √3 cm.
Determine the area of the trapezoid.
Savsd = (ВС + АD) * СН / 2 = (10 + 12) * 2 * √3 / 2 = 22 * √3 cm2.
Answer: The area of the trapezoid is 22 * √3 cm2.
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