AD and CE are the bisectors of the isosceles triangle ABC. AC – base. Prove that triangle AEC = triangle CDA.

Consider triangles AEC and CDA, in them:
AC – common side;
∠EAC = ∠DСА (angles at the base of an isosceles triangle ABC);
∠ECA = ∠DCA (formed by bisectors of equal angles).
We have a second feature (along the side and adjacent corners).
Triangles AEC and CDA are equal, as required.



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