AD-bisector angle C = 30 degrees, angle BAD = 22 degrees. Find ADB Angle

In triangle ABC, AD is the bisector, so since the angle ABD is 22 °, the angle ADC is also 22 °.

Consider a triangle ADC, in which the angle ADC = 22 ° and the angle ACD = 30 ° (according to the problem statement). Angle ADB external for triangle ADC, it is equal to the sum of two internal, not adjacent to it:

ADB angle = ADC angle + ACD angle = 22 ° + 30 ° = 52 °