After burning 6.82 red phosphorus in oxygen from the walls of the vessel in which the reaction was carried out

After burning 6.82 red phosphorus in oxygen from the walls of the vessel in which the reaction was carried out, it was possible to collect 14.2 g of phosphorus oxide. Determine the mass fraction of the reaction yield.

The production of phosphorus oxide is described by the following chemical reaction equation (CCR):

4P + 5O2 = 2P2O5;

4 moles of phosphorus react with 5 moles of oxygen. In this reaction, 2 moles of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance contained in phosphorus weighing 62 grams.

M P = 31 grams / mol;

N P = 6.82 / 31 = 0.22 mol;

From this amount of phosphorus, 0.22 / 2 = 0.11 mol of its oxide will be synthesized.

Let’s calculate its weight. To do this, multiply the amount of the substance by the weight of 1 mole (its molar weight).

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

m P2O5 = 0.11 x 142 = 15.62 grams;

The reaction yield is 14.2 / 15.62 = 0.91 = 91%;