After launch, the rocket climbed vertically upward within 5 minutes at a speed equal to 8 km / s.

After launch, the rocket climbed vertically upward within 5 minutes at a speed equal to 8 km / s. How is the acceleration directed in this case and what is its value?

These tasks: t (duration of the rocket rise) = 5 min (in SI t = 300 s); V (the speed of the rocket in question at time t) = 8 km / s (8000 m / s).

The acceleration of the rocket after launch was directed upward and is determined by the formula: V = V0 + a * t = 0 + a * t, whence a = V / t.

Let’s perform the calculation: a = 8000/300 = 26.67 m / s2.

Answer: The acceleration of the rocket under consideration is 26.67 m / s2.