After leaving the station, the train covered a distance of 562.5 m. How long did it take if it moved

After leaving the station, the train covered a distance of 562.5 m. How long did it take if it moved with an acceleration of 5 m / s2.

To determine the time it took for a given train to travel a distance of 562.5 m, we apply the formula: S = V0 * t + a * t ^ 2/2, where S is the distance traveled (S = 562.5 m); V0 – initial speed (V0 = 0 m / s, the train was leaving the station); a – acceleration (a = 5 m / s2).

Let us express the time of movement: S = V0 * t + a * t ^ 2/2 = 0 + a * t ^ 2/2, whence t = √ (2S / a).

Let’s make a calculation: t = √ (2 * 562.5 / 5) = √225 = 15 s.

Answer: The train took 15 seconds.