After loading two identical harvesters on a 40 m long and 10 m wide ferry, he plunged 10 cm

After loading two identical harvesters on a 40 m long and 10 m wide ferry, he plunged 10 cm into the water. Find the weight of the harvester.

Data: L (ferry length) = 40 m; B (ferry width) = 10 m; Δh (change in the ferry draft) = 10 cm (in SI Δh = 0.1 m); n (number of identical combines) = 2 pcs.

Constants: ρw (water density) = 1000 kg / m3.

To determine the mass of one combine, we use the equality: ΔFa = ΔFт.

ρw * g * V = n * m * g.

ρw * L * B * Δh = n * m.

m = ρw * L * B * Δh / n.

Let’s perform the calculation: m = 1000 * 40 * 10 * 0.1 / 2 = 20 * 10 ^ 3 kg (20 tons).

Answer: Each of the harvesters has a mass of 20 tons.