After passing 4.48 liters of sulfur dioxide through the barium hydroxide solution, 252.8 g of potassium

| March 17, 2021 | education

After passing 4.48 liters of sulfur dioxide through the barium hydroxide solution, 252.8 g of potassium sulfite solution were obtained. Calculate the mass fraction in the resulting solution.

Let’s find the amount of the substance sulfur dioxide SO2.

n = V: Vn.

n = 4.48 L: 22.4 L / mol = 0.2 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2KOH + SO2 = K2SO3 + H2O.

According to the reaction equation, 1 mol of SO2 accounts for 1 mol of K2SO3. Substances are in quantitative ratios 1: 1.

n (K2SO3) = n (SO2) = 0.2 mol.

Let’s find the mass of K2SO3.

m = n × M,

M (K2SO3) = 158 g / mol.

m (K2SO3) = 158 g / mol × 0.2 mol = 31.6 g.

Find the mass fraction of K2SO3 in the solution.

W = m (substance): m (solution) × 100%,

W = (31.6 g: 252.8 g) 100% = 12.5%.

Answer: 12.15%.



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