After passing 5.6 l of ammonia through a solution of sulfuric acid with a mass fraction of 10%, a solution of a medium

After passing 5.6 l of ammonia through a solution of sulfuric acid with a mass fraction of 10%, a solution of a medium salt was obtained. Determine the mass of the initial sulfuric acid solution

2NH3 + H2SO4 = (NH4) 2SO4

n (NH3) = 5.6 / 22.4 = 0.25 mol;

m (NH3) = n (NH3) * M (NH3) = 0.25 * 17 = 4.25 g;

n ((NH4) 2SO4) = 0.5n (NH3) = 0.125 mol

m ((NH4) 2SO4) = n ((NH4) 2SO4) * M ((NH4) 2SO4) = 0.125 * 132 = 16.5 g;

m ((NH4) 2SO4 solution) = 16.5 / 0.1 = 165 g;

m (H2SO4 solution) = m ((NH4) 2SO4 solution) – m (NH3) = 165 – 4.25 = 160.75 g.

Answer: m (H2SO4 solution) = 160.75 g.