After passing through a solution of sodium hydroxide 4, 48 liters of carbon dioxide received 300 g of sodium carbonate

After passing through a solution of sodium hydroxide 4, 48 liters of carbon dioxide received 300 g of sodium carbonate solution. Calculate the mass fraction of salt in the resulting solution.

1.CO2 + 2NaOH => Na2CO3 + H2O
2.n (CO2) = V / Vm = 4.48 / 22.4 = 0.2 mol
3.n (Co2) / 1 = n (Na2CO3) / 1 n (Na2CO3) = 0.2 mol
4.m (Na2CO3) mass of pure substance = nM = 0.2 × 106g / mol = 21.2g M (Na2CO3) = 23 × 2 + 12 + 16 × 3 = 106g / mol
5.W (Na2CO3) = m (pure substance) / m (solution) × 100% = 21.2 / 300 × 100% = 0.07 × 100% = 7%