# After passing through the sulfuric acid solution 0.448 l of ammonia. 66 g of ammonium sulfite

**After passing through the sulfuric acid solution 0.448 l of ammonia. 66 g of ammonium sulfite solution were obtained. Calculate the mass fraction of salt in the resulting solution.**

Ammonia reacts with sulfuric acid. This synthesizes the ammonium sulfate salt.

This reaction proceeds according to the following chemical reaction equation:

2NH3 + H2SO4 = (NH4) 2SO4;

Let’s determine the chemical amount of ammonia. To do this, we divide its volume by the standard volume of 1 mole of gas (filling 22.40 liters)

N NH3 = 0.448 / 22.4 = 0.02 mol;

From this amount of ammonia, 0.02 / 2 = 0.01 mol of ammonium sulfate can be obtained.

Let’s calculate its weight.

For this purpose, we multiply the chemical (molar) amount of a substance by its molar (atomic) mass.

M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;

The weight of ammonium sulfate will be:

m (NH4) 2SO4 = 132 x 0.01 = 1.32 grams;

The mass fraction of salt will be 1.32 / 66 = 0.02 = 2%;