After passing through the sulfuric acid solution 0.448 l of ammonia. 66 g of ammonium sulfite

After passing through the sulfuric acid solution 0.448 l of ammonia. 66 g of ammonium sulfite solution were obtained. Calculate the mass fraction of salt in the resulting solution.

Ammonia reacts with sulfuric acid. This synthesizes the ammonium sulfate salt.
This reaction proceeds according to the following chemical reaction equation:
2NH3 + H2SO4 = (NH4) 2SO4;
Let’s determine the chemical amount of ammonia. To do this, we divide its volume by the standard volume of 1 mole of gas (filling 22.40 liters)
N NH3 = 0.448 / 22.4 = 0.02 mol;
From this amount of ammonia, 0.02 / 2 = 0.01 mol of ammonium sulfate can be obtained.
Let’s calculate its weight.
For this purpose, we multiply the chemical (molar) amount of a substance by its molar (atomic) mass.
M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;
The weight of ammonium sulfate will be:
m (NH4) 2SO4 = 132 x 0.01 = 1.32 grams;
The mass fraction of salt will be 1.32 / 66 = 0.02 = 2%;

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