# After the impact, the puck received 20 m / s, after 2 seconds the speed is 16 m / s.

October 7, 2021 | education

| **After the impact, the puck received 20 m / s, after 2 seconds the speed is 16 m / s. determine acceleration, distance and time to stop.**

Data: V0 (velocity after impact, initial velocity) = 20 m / s; t1 (elapsed time) = 2 s; V1 (speed at time t1) = 16 m / s.

1) Determine the acceleration: V1 = V0 – a * t1, whence a = (V0 – V1) / t1 = (20 – 16) / 2 = 2 m / s2.

2) Calculate the path traveled by the puck: S = (V0 ^ 2 – V2) / 2a = (20 ^ 2 – 02) / (2 * 2) = 100 m.

3) Calculate the time until the puck comes to a complete stop: t = (V0 – V) / a = (20 – 0) / 2 = 10 s.

Answer: The washer was moving with an acceleration of 2 m / s2; the path is 100 m; the time to stop is 10 s.

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