After the push, the car stopped, having passed 60 m horizontally in 20 seconds. What is the coefficient of friction?

Ftp = ma
S = V * t-at ^ 2/2
V = (S / t + at / 2) = at
a = 2S / t ^ 2
Ftp = kmg = ma
From here the coefficient of friction can be found:
K = a / g = 2S / gt ^ 2 = 2 * 60/10 * 20 ^ 2 = 0.03
Answer: k = 0.03



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