After the push, the car stopped passing 37.5 m horizontally in 50 seconds. what is the coefficient of friction?

Initial data: S (horizontal distance traveled by the car) = 37.5 m; t (duration of the carriage) = 50 s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The coefficient of sliding friction is determined from the equality: Ftr. = μ * m * g = m * a = m * 2 * S / t ^ 2 and μ = 2 * S / (g * t ^ 2).

Let’s calculate: μ = 2 * 37.5 / (10 * 50 ^ 2) = 0.003.

Answer: The coefficient of friction is 0.003.