After the push, the sled moves along a horizontal path. How will the modulus of the sled’s impulse change

After the push, the sled moves along a horizontal path. How will the modulus of the sled’s impulse change if a friction force on the snow, equal to 20 N, acts on them for 5 s?

Data: t (duration of the action of the friction force on the sled) = 5 s; Ffr (friction force) = 20 N.

To determine the desired change in the modulus of the sled’s impulse, we use the formula: ΔP = m * ΔV = m * (F * t / m) = F * t.

Let’s calculate: ΔP = 20 * 5 = 100 kg * m / s.

Answer: The module of the sled’s impulse will decrease by 100 kg * m / s.