After unloading, the barge rose from the water by 1m. Determine the weight of the cargo removed from the barge

After unloading, the barge rose from the water by 1m. Determine the weight of the cargo removed from the barge, assuming the barge’s cross-sectional area at the water level is constant and equal to 350m2.

These tasks: Δh (change in the draft of the considered barge after unloading) = 1 m; S (cross-sectional area at water level) = 350 m2.

Constants: ρw (water density) = 1000 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

To determine the weight of the cargo removed from the barge under consideration, we use the equality: ΔFt = Pg = ΔFa; Pg = ρw * g * ΔV = ρw * g * S * Δh.

Let’s perform the calculation: Pg = 1000 * 10 * 350 * 1 = 3.5 * 10 ^ 6 N (3.5 MN).

Answer: A cargo weighing 3.5 MN was removed from the barge.